Termination w.r.t. Q proof of TRS/SK904.49.trs

Termination w.r.t. Q of the following Term Rewriting System could not be shown:

Q restricted rewrite system:
The TRS R consists of the following rules:

f(x, y, f(z, u, v)) → f(f(x, y, z), u, f(x, y, v))

Q is empty.

↳ QTRS

  ↳ DependencyPairsProof

Q restricted rewrite system:
The TRS R consists of the following rules:

f(x, y, f(z, u, v)) → f(f(x, y, z), u, f(x, y, v))

Q is empty.

Using Dependency Pairs [1,13] we result in the following initial DP problem:
Q DP problem:
The TRS P consists of the following rules:

F(x, y, f(z, u, v)) → F(x, y, v)
F(x, y, f(z, u, v)) → F(x, y, z)
F(x, y, f(z, u, v)) → F(f(x, y, z), u, f(x, y, v))

The TRS R consists of the following rules:

f(x, y, f(z, u, v)) → f(f(x, y, z), u, f(x, y, v))

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

↳ QTRS

  ↳ DependencyPairsProof

    ↳ QDP

Q DP problem:
The TRS P consists of the following rules:

F(x, y, f(z, u, v)) → F(x, y, v)
F(x, y, f(z, u, v)) → F(x, y, z)
F(x, y, f(z, u, v)) → F(f(x, y, z), u, f(x, y, v))

The TRS R consists of the following rules:

f(x, y, f(z, u, v)) → f(f(x, y, z), u, f(x, y, v))

Q is empty.
We have to consider all minimal (P,Q,R)-chains.